"At least one 'end' is missing: the statement may begin here"

Question

Cole Bromfield 2020-1-13

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/500118-at-least-one-end-is-missing-the-statement-may-begin-here

评论： stozaki 2020-1-13

k=1
for k=1:20
    disp(k)
    if mod(k,2)==0
    disp("na")
    if mod(k,3)==0
    disp("ba")
    if mod(k,5)==0
    disp("mo")
    else
    disp("gano")
    end
end

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Answer 1

stozaki 2020-1-13

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/500118-at-least-one-end-is-missing-the-statement-may-begin-here#answer_409928

在 MATLAB Online 中打开

Please try following script.

k=1
for k=1:20
    disp(k)
    if mod(k,2)==0
    disp("na")
    elseif mod(k,3)==0
    disp("ba")
    elseif mod(k,5)==0
    disp("mo")
    else
    disp("gano")
    end
end

Conditional Statements

Regards,

stozaki

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Cole Bromfield 2020-1-13

I need it to display every syllable that applies though. For example, if a number is divisible by both 2 and 5, I need "namo" to be displayed. With that code, it just displays "na"

stozaki 2020-1-13

在 MATLAB Online 中打开

How about using the highest priority decision in the if clause?

k=1
for k=1:20
    disp(k)
    if mod(k,5)==0 && mod(k,2)==0
        disp("namo")
    elseif mod(k,3)==0
        disp("ba")
    elseif mod(k,5)==0
        disp("mo")
    elseif mod(k,2)==0
        disp("na")
    else
        disp("gano")
    end
end