What is wrong with my "if is integer" code

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I have a function roman= dectoroman(number) I want first to test out for if the number is an interger or not and I tried using the isinteger function but somehow its not working and not really sure why.
if isinteger(number)
x = [ 1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]; % Array of intergers (x)
y = {'M', 'CM', 'D', 'CD', 'C', 'XC', 'L', 'XL', 'X', 'IX', 'V', 'IV', 'I'};% array of strings equalling intergers above respectivly (y)
roman=[];%Instantiating
for ii = 1:numel(x)
number >= x(ii);
roman = [roman,repmat(y{ii},1,fix(number/x(ii)))];
number = rem(number,x(ii));
else
error('error')
end
end
end
wondering if there was anyway to test if its not an integer so i can just go if its to an integer ---> error end

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2012-10-8
编辑:Azzi Abdelmalek 2012-10-8
because
isinteger(1)=0 % for example
try
if fix(a)==a

更多回答(1 个)

Walter Roberson
Walter Roberson 2012-10-8
A number is an integer if mod(number,1) == 0

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