ho to apply upper boundary for cumulaitive percentage

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liyana nadirah 2020-1-31

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https://ww2.mathworks.cn/matlabcentral/answers/502923-ho-to-apply-upper-boundary-for-cumulaitive-percentage

评论： Pravin Jagtap 2020-2-4

l=input('l=')
g =  zeros(1, length(0:100));% initialize g with 0's of length t
c = 1;% counter variable
for t=0:100
    if t>2 && t<=80
        g(c)=((3/(309*1.465))*((((12.6*(t-2))/l)*80.4)-(l/6)));
    elseif t>80
        g(c)=1-((80.4/309)*exp(((((-3*12.6)/(1.465*l))*(t-80)))));
    else
        g(c)=0;
    end
    c = c+1;% increment counter variable
end
format shortG
g
t=0:100;
gs = cumsum(g);
gs = gs / gs(end) * 100;
plot(t,gs,'r')
xlabel('Day')
ylabel('Cumulative percentage of nutrient release,%')

this is my coding and i have to apply the up boundary for cumulative percentage of g which is 73%. so can someone help me

4 个评论
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Rik 2020-1-31

You will have to be a little bit more verbose. When I run your code (setting L to 1), I don't see anything related to 73% showing up. I get a normal graph, so I don't see your issue.

Relatedly, you really shouldn't use a lower case L as a variable name. It is difficult to distinguish from the number 1.

Pravin Jagtap 2020-2-4

Hello Liyana,

The statement 'i have to apply the up boundary for cumulative percentage of g which is 73%' is not clear. I found the attached output for 'l=2'. Does that mean you dont want values in g vector above 73? We need some more clarity on question.