I get the warning 'Function behaves unexpectedly on array inputs.' when using fplot()
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Why do I get a warning when using fplot() in my code:
function solution_heat_equation(t)
f = @(x,y) (exp((-abs(x-y).^2)./(4.*t))).*u_0(y);
a = -10;
b = 10;
z = @(x) integral(@(y) f(x,y) , a,b);
u = @(x) (1/sqrt(4*pi*t))*z(x)
fplot(u)
function val = u_0(x)
if abs(x)<1
val = 1;
else
val = 0;
end
I get the following warning and I don't get a plot of my function:
Warning: Function behaves unexpectedly on array inputs. To improve performance, properly
vectorize your function to return an output with the same size and shape as the input
arguments.
> In matlab.graphics.function.FunctionLine>getFunction
In matlab.graphics.function/FunctionLine/updateFunction
In matlab.graphics.function.FunctionLine.set.Function_I
In matlab.graphics.function.FunctionLine.set.Function
In matlab.graphics.function.FunctionLine
In fplot>singleFplot (line 245)
In fplot>@(f)singleFplot(cax,{f},limits,extraOpts,args) (line 200)
In fplot>vectorizeFplot (line 200)
In fplot (line 166)
In solution_heat_equation (line 8)
采纳的回答
Star Strider
2020-2-2
With a scalar ‘t’, there are no problems provided that ‘z’ sets 'ArrayValued' to true in the integral call, and ‘u’ is vectorised:
z = @(x) integral(@(y) f(x,y) , a,b, 'ArrayValued',1);
u = @(x) (1./sqrt(4*pi*t)).*z(x);
The rest of your code is unchanged.
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