for i = dec
disp([i,dates(i).Month])
end
This might be enough for your situation. However, it is very common to need to have one output for each non-consecutive input. In such a case, you should learn this kind of pattern:
decvals = find etc
numdec = length(decvals);
outputs = zeros(numdec, 1);
for decidx = 1 : numdec
dec = decvals(decidx);
do something with dec
outputs(decidx) = whatever;
end
In this kind of pattern, decvals does not need to be consecutive or integer or unique -- it does not even need to be real-valued or numeric. This kind of pattern will loop through all of whatever values are there, extracting one at a time (here into the variable dec) and storing the output computed into the location corresponding to the offset into the array of values.
