How to sort a matrix in desceding order?

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SM
SM 2020-2-9
评论： SM 2020-2-9
I have a matrix such as:
A =[
0.8604 0.5134 0.9391 0.6482 0.3479 0.3308 0.7069 0.7640 0.0567 0.9052
0.9344 0.1776 0.3013 0.0252 0.4460 0.8985 0.9995 0.8182 0.5219 0.6754
0.9844 0.3986 0.2955 0.8422 0.0542 0.1182 0.2878 0.1002 0.3358 0.4685
0.8589 0.1339 0.3329 0.5590 0.1771 0.9884 0.4145 0.1781 0.1757 0.9121
0.7856 0.0309 0.4671 0.8541 0.6628 0.5400 0.4648 0.3596 0.2089 0.1040];
if i use
[~, sortOrder] = sort(A(1,:), 'descend')
then it gives
sortOrder=[3 10 1 8 7 4 2 5 6 9];
but if i apply this code for all rows such as
[~, sortOrder] = sort(A(:), 'descend')
it shows results which i dont want.
How can i solve it if i want the following outcome:
sortOrder=
[3 10 1 8 7 4 2 5 6 9
7 1 6 8 10 9 5 3 2 4
1 4 10 2 9 3 7 6 8 5
6 10 1 4 7 3 8 5 9 2
4 1 5 6 3 7 8 9 10 2];
No for loop please! I use R2017b.
Thanks in advance!

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采纳的回答

Walter Roberson
Walter Roberson 2020-2-9
[~, sortOrder] = sort(A, 2, 'descend');

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