Extracting string and number pairs from a mixed string

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Dear all,
I have read in material data and have gotten an array of chemical compositions of the type (chr):
'Fe61Zr8Co7Mo15B7Y2' sometimes even '(Fe0.5Co0.5)58.5Cr14Mo6C15B6Er0.5' wherein Fe and Co have a percentage of 29.25 (58.5*0.5...).
How do I extract the chemical composition so that I receive an array (or two) like
['Fe', 'Zr', 'Co', 'Mo', 'B', 'Y'; 61, 8, 7, 15, 7, 2]?
I am somehow failing to use sscanf correctly, e.g. numbers = sscanf('Fe61Zr8Co7Mo15B7Y2', '%f') won't do anything since I need to omit varying strings :(
Thanks a lot in advance!
Greetings
Lukas

采纳的回答

Stephen23
Stephen23 2020-2-13
编辑:Stephen23 2020-6-15
The two lines marked with %%% are used to convert substrings like '(Fe0.5Co0.5)58.5' into 'Fe29.25Co29.25', after which the designator+number matching and extraction is easy:
>> str = '(Fe0.5Co0.5)58.5Cr14Mo6C15B6Er0.5';
>> baz = @(s,b)regexprep(s,'(\d+\.?\d*)','${num2str(str2double($1)*str2double(b))}'); %%%
>> tmp = regexprep(str,'\((([A-Z][a-z]*\d+\.?\d*)+)\)(\d+\.?\d*)','${baz($1,$2)}'); %%%
>> out = regexp(tmp,'([A-Z][a-z]*)(\d+\.?\d*)','tokens');
>> out = vertcat(out{:})
out =
'Fe' '29.25'
'Co' '29.25'
'Cr' '14'
'Mo' '6'
'C' '15'
'B' '6'
'Er' '0.5'
>> str2double(out(:,2)) % optional
ans =
29.25
29.25
14
6
15
6
0.5
The code uses two layers of dynamic regular expression, the first calls baz for each each '(AxBy...)N' substring, then inside baz each of x, y, etc. is multiplied with N. The result is converted to char for reinsertiion.
  6 个评论
Stephen23
Stephen23 2020-6-15
编辑:Stephen23 2020-6-15
The reason is that I missed a question mark here:
tmp = regexprep(str,'\((([A-Z][a-z]*\d+\.?\d*)+)\)(\d+\.?\d*)','${baz($1,$2)}')
% ^ missing
which meant that the regular expression did not match integer numbers, only numbers with a decimal point.
With that question mark in place (I have now corrected the question and comments), this is the output:
>> out = regexp(tmp,'([A-Z][a-z]*)(\d+\.?\d*)','tokens');
>> out = vertcat(out{:})
out =
'Fe' '6550.4'
'B' '2208'
'Y' '441.6'
'Nb' '8'
"Another issue are compositions which contain more "subcompositions" and are separated by other brackets."
Regular expressions alone are not really suitable for this. For parsing arbitrarily nested brackets like that you will probably have to write your own string parser, e.g. based on a recursive function which uses regular expressions or other string manipulation inside it. Have you worked with recursive functions before?
Чебура́шка, да!
LukasJ
LukasJ 2020-6-15
编辑:LukasJ 2020-6-15
But this output is also wrong! The numbers should sum-up to 1 or 100 and the proportion of Fe should then be 0.65504. The complete output should be:
out =
'Fe' '0.65504'
'B' '0.2208'
'Y' '0.04416'
'Nb' '0.08'
The issues come from the inconsistent notation in the dataset I guess :(.
"Have you worked with recursive functions before?"
I vaguely remember writing the Fibonacci-series as a function during my bachelor studies... But I don't think I'm capable of applying any of that on this problem in a finite amount of time :D
I will probably just iterate over all the "unclear" cases where { and [ occur, extract whats inside and then apply your function.
e.g. match
regexp = '\{.+\}'
And then check what's inside.
At least that would be feasible for me to do :)

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更多回答(1 个)

LukasJ
LukasJ 2020-2-13
ok so
numbers = str2double(regexp(myString,'[\d.]+','match')); does give me the numbers
but
words = regexp(myString,'[\w*]+','match')); does not give me the chemical notations, probably because those aren't "words" :/

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