I have a matrix that contains strings and i have to find words in it.
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I have to create a program that gives you the position of the first letter of the word you input and if it's from left to right or right to left.
for example if you input the word 'er' it should tell you that:
The word was found from left to right at the position (1,1)
Please help
['e' 'r' 'd' 'u' 'o' 'p' 'i' 'e' 'c' 'e';...
't' 'p' 'r' 'o' 'm' 'e' 't' 'a' 'l' 'l';...
'i' 's' 'd' 'p' 's' 't' 'u' 'b' 'a' 'a';...
'g' 'e' 'p' 'o' 'm' 's' 'i' 'c' 'm' 'v';...
's' 't' 'e' 'i' 'u' 'r' 'a' 't' 'e' 'a';...
'o' 't' 'n' 'n' 'c' 'b' 'c' 'b' 'r' 'g';...
'u' 'e' 'f' 'c' 't' 'e' 'l' 'u' 'l' 'e';...
'v' 'l' 'i' 'o' 'r' 'b' 'r' 'o' 'i' 'e';...
'e' 'l' 'e' 'n' 'u' 'u' 'i' 'r' 'n' 't';...
'r' 'i' 'v' 'i' 'e' 'r' 'e' 'j' 'g' 'a';...
'a' 'a' 'r' 'n' 'e' 'l' 'r' 'r' 'o' 'c';...
'i' 'p' 'e' 'c' 'a' 'r' 'a' 't' 't' 'u';...
'n' 't' 'e' 'g' 'a' 'i' 'l' 'l' 'a' 'd';...
'f' 'i' 'l' 'o' 'n' 'o' 'l' 'a' 't' 'e']
2 个评论
Mil Shastri
2020-2-19
Hi Ziyad, could you rephrase your question. It's not very clear.
Also, consider checking out a previous discussion: https://www.mathworks.com/matlabcentral/answers/231706-finding-position-of-a-string-in-a-cell-array
Stephen23
2020-3-3
编辑:Stephen23
2020-3-3
The character array shown in the question can be written more simply as:
['erduopiece';...
'tprometall';...
'isdpstubaa';...
'gepomsicmv';...
'steiuratea';...
'otnncbcbrg';...
'uefctelule';...
'vliorbroie';...
'elenuuirnt';...
'rivierejga';...
'aarnelrroc';...
'ipecarattu';...
'ntegaillad';...
'filonolate']
or:
['erduopiece';'tprometall';'isdpstubaa';'gepomsicmv';'steiuratea';'otnncbcbrg';'uefctelule';'vliorbroie';'elenuuirnt';'rivierejga';'aarnelrroc';'ipecarattu';'ntegaillad';'filonolate']
采纳的回答
Jalaj Gambhir
2020-3-3
Hi,
matrix = ['a','b','d','f';
'c','t','a','g';
'f','a','n','p';
'd','b','a','b'];
word = 'ab';
for i=1:length(matrix)
str = matrix(i,:);
idxL2R = strfind(str,word);
idxR2L = strfind(str,flip(word));
result = ['for string = ',str,' indexL2R while searching for word = ',word,
' is = ',int2str(idxL2R), ' indexR2L is = ', int2str(idxR2L)];
disp(result);
end
2 个评论
Jalaj Gambhir
2020-3-3
Result:
for string = abdf indexL2R while searching for word = ab is = 1 indexR2L is =
for string = ctag indexL2R while searching for word = ab is = indexR2L is =
for string = fanp indexL2R while searching for word = ab is = indexR2L is =
for string = dbab indexL2R while searching for word = ab is = 3 indexR2L is = 2
更多回答(1 个)
Stephen23
2020-3-3
>> mat = ['erduopiece';'tprometall';'isdpstubaa';'gepomsicmv';'steiuratea';'otnncbcbrg';'uefctelule';'vliorbroie';'elenuuirnt';'rivierejga';'aarnelrroc';'ipecarattu';'ntegaillad';'filonolate'];
>> baz = @(r,c)[r*ones(numel(c),1),c(:)];
>> vec = num2cell(1:size(mat,1));
>> fun = @(s)cell2mat(cellfun(baz,vec(:),strfind(num2cell(mat,2),s),'uni',0)).';
>> str = 'er';
>> fprintf('The word was found from left to right at the position (%u,%u)\n',fun(str))
The word was found from left to right at the position (1,1)
The word was found from left to right at the position (10,5)
>> fprintf('The word was found from right to left at the position (%u,%u)\n',fun(fliplr(str)))
The word was found from right to left at the position (10,6)
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