Reshaping a 2 d matrix into a 3 d matrix row wise.

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Russ
Russ 2020-2-21
评论： Russ 2020-2-21
Hello, and thanks for taking the time to read this:
I have a 100 x 99 matrix of ratings. I would like to reshape the matrix into a 9x11x100 array where the first row represents the first 9 horizsontal items of the first row. Byu way of a smaller example, imagine the data were:
7 6 5 4 5 6
1 5 6 6 6 2
1 6 6 6 6 1
5 5 6 6 7 2
I would like the result to be:
765
456
156
662
556
672
Can anyone please help with this?

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采纳的回答

the cyclist
the cyclist 2020-2-21
编辑：the cyclist 2020-2-21
For your small example, if A is your original matrix, then
permute(reshape(A',3,2,[]),[2 1 3])
For the larger one,
permute(reshape(A',9,11,[]),[2 1 3])
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the cyclist
the cyclist 2020-2-21
Yes, I see you effectively have these two conflicting statements in your question:
  • result is 9x11x100
  • first row is the first 9 items
These are conflicting because if the result is 9x11x100, then the first row has 11 items.
But it sounds like you got what you needed.
Russ
Russ 2020-2-21
Yep, now I understand where I went wrong. The first row was supposed to be the first 11 items, not the first 9 items. Thanks so much for solving this problem!

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更多回答（1 个）

Daniel Vieira
Daniel Vieira 2020-2-21
A=randi(10,100,99); % example of what your matrix might be
B=permute(reshape(A',9,11,[]),[2 1 3]) % solution
  1 个评论
Russ
Russ 2020-2-21
Thanks! The following alternative seemed to do the trick.
permute(reshape(A', 11,9,[]), [2 1 3])
Thanks!
Russ

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