Delete and merge rows and columns based on values of other matrix under looop

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vimal r 2020-2-24

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https://ww2.mathworks.cn/matlabcentral/answers/507272-delete-and-merge-rows-and-columns-based-on-values-of-other-matrix-under-looop

评论： Turlough Hughes 2020-2-24

i have a matrix of A and B1 B2 B3....Bn condition is to check B1 if zero then eliminate the rows and columns in matrix A store as A1 then it should go to B2 check and store in A2 till An.

A is nxn matrix

B1 B2.....Bn is a 1xn

Example:

if any of the element in B1 matrix is zero suppose element 3 it should eliminate 3rd row and 3rd column of Matrix A and store as A1

and it has to loop till Bn and store An matrices.

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vimal r 2020-2-24

i have to store An matrix loop should end n variable output of A1 ....An based on the condition of Bnxn each row as one senario...

my input is Anxn and Bnxn

take first row of B check zeros and based on that it should eliminate rows and columns in matrix A and store as A1

then go to second row of B check and based on zero eliminate rows and columns in matrix A and store as A2

so on.....

Turlough Hughes 2020-2-24

The code I provided above does what you ask with the exception of working through columns of B as opposed to rows of B because I did not have enough info at the time... that's is a simple fix. Having variables numbered A1 to An is a sign that you are doing something wrong because you either have to copy and paste code or use the eval function to generate these variables.

https://uk.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

The results in the example I provided above are stored in a cell array which is in my opinion the easiest alternative to generating n variables. The results are then equivalently stored as

An{1,1}, An{1,2} all the way up to An{1,n}.

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