storing fprintf as an array.

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Jide Williams
Jide Williams 2020-3-3
评论： Jide Williams 2020-3-3
The outcome of the code below gives H T H T T depending on random function. How do I store the outcome of the 20 iterations into a variable called 'product' ; for example: product =[ H T H T T......] so that whenever I need it, I can fetch the outcome by just typing 'product'
fprintf('The Outcomes are:\n')
for i = 1:20
A = rand(i,1);
if A(i) >= 0.5000
fprintf('%s\n', 'H');
else
fprintf('%s\n', 'T');
end
end

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采纳的回答

David Hill
David Hill 2020-3-3
Why do a loop?
product=rand(1,20);
product(product>=.5)=72;
product(product<.5)=84;
product=char(product);
  1 个评论
Jide Williams
Jide Williams 2020-3-3
Thanks, i needed the for loop because I want to perform a Monte Carlo Analysis. This is better in loops

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更多回答（1 个）

Walter Roberson
Walter Roberson 2020-3-3
Outcome(i) = 'H';
The closest to your current code would be
Outcome{i} = sprintf('%s\n', 'H') ;
  4 个评论
显示 2更早的评论
Walter Roberson
Walter Roberson 2020-3-3
No. You call
A = rand(i, 1)n
That defines A to be a column vector of random numbers with i values in the vector. In the next line you access A(i) which is only the last of those values and not any of the values before that. But when you are examining to see whether the code works, you are reading off the first of the values, not the last. Or perhaps after the loop you are examining A, but since you overwrite all of A each time, the values that were used to make the decision have been thrown away and replaced by new values before you look.
Your code should be:
A(i) = rand(1,1);
Jide Williams
Jide Williams 2020-3-3
Yeah i have seen my mistakes. Thans

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