Why did imread() stop working when I changed to 2019a?

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Chuck37
Chuck37 2020-3-10
编辑： Chuck37 2020-3-11
I have been using imread to get images from a server by putting requests into the URL argument: im = imread(url). Now I'm getting an error "Can't read URL, ..., Reason: first input must be 1xN cell array of strings." What is it talking about?
EDIT: I wasted everyone's time with this. After digging deeper, I found that I had an old version of strjoin() in my path somehow. The function must have changed in a critical way. Problem disappeared when I removed this old version.
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Chuck37
Chuck37 2020-3-10
I believe that this is not due to going to 2019a, but related to recent permission lockdowns on /tmp directory (linux). I need to figure out how to point matlab to a different temp directory to test this.

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回答（1 个）

Steven Lord
Steven Lord 2020-3-10
Can you show us the class and size of the url variable you're passing into imread?
Is it a character vector or a string scalar as the documentation page for the imread function indicates it needs to be? See the section describing the Input Arguments, specifically the filename input argument.
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Image Analyst
Image Analyst 2020-3-10
It looks like that would not give a simple filename, but possibly a list of a whole bunch of filenames. I suggest you somehow use webread() to execute that query and then parse out the filenames one at a time.
Chuck37
Chuck37 2020-3-10
编辑：Chuck37 2020-3-10
No, it just gives back one jpeg file. It used to work just fine (for years). I jumped from 2016a to 2019a.
I was experimenting and webread gives the same error anyway. I can't say I understand why there is so much code to rip the URL into pieces and glue it back together. webread does the same.
EDIT: urlread functions without error, but it just gives me a character vector, presumably raw jpeg bytes, which isn't all that helpful and would require a bit of workaround to make into pixels.

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