column extraction in matlab

1 次查看（过去 30 天）
PK
PK 2012-10-17
can some one help in this my Fitness values are Fitness =
0.0443
0.0473
0.0475
0.0475
0.0476
0.0475
0.0443
0.0476
0.0473
0.0467 and these are fitness values of a 10x100 matrix each fitness value corresponds to a single row and the fitness values changes in every execution and for current execution the min value is at 1st position but for next execution it may change so that the minimum valued fitness row should be extracted and placed in a variable i tried it with for loop but not fetting result and it is as below
Fitness=calculateFitness(ObjVal);
indx=find(Fitness==min(Fitness));
row=Foods;
for indx=1;row=Foods(1,:);
indx=2;row=Foods(2,:);
indx=3;row=Foods(3,:);
indx=4;row=Foods(4,:);
indx=5;row=Foods(5,:);
indx=6;row=Foods(6,:);
indx=7;row=Foods(7,:);
indx=8;row=Foods(8,:);
indx=9;row=Foods(9,:);
indx=10;row=Foods(10,:);
end
pbest=row;

请先登录，再回答此问题。

采纳的回答

Walter Roberson
Walter Roberson 2012-10-17
Something like
for indx = 1 : 10
row = Foods(indx,:);
end
  3 个评论
显示 1更早的评论
Walter Roberson
Walter Roberson 2012-10-17
Ah, perhaps you just meant
row = Foods(indx,:);
You coded a "for" loop, and "for" loops have to do with iteration. If you want to test values and do different things for different values, use "switch"
PK
PK 2012-10-17
k fine and in the same program the command indx=find(Fitness==min(Fitness)); states that location of min fitness is to be stored in the variable called indx but its not happening so and in the command window if i reun the statement find(Fitness==min(Fitness)) it shows exact location but not showing exact location of min fitness all the time when i run the code y so that happens

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by