access the respective values of matrix using the cell array cell position value

1 次查看(过去 30 天)
i have a matrix as shown in figure, with positions marked
I have a cell array with values
{ [ 1 4 ] ; [ 2 3] };
Now i want to take the values from position
{ [0-1 1-4] ; [0-2 2-3] } of the matrix
i.e. { [ 33 45]; [34 30] }
and get the sum of
33 + 45 +34 +30 = 142
how can i access the respective values of matrix using the cell array cell position values?

采纳的回答

Sriram Tadavarty
Sriram Tadavarty 2020-3-17
编辑:Sriram Tadavarty 2020-3-17
Hi Elysi,
Here is what you have asked for
% Given matrix
a = [0 33 34 16 25;...
22 0 20 12 45;...
20 40 0 30 12;...
16 12 30 0 44;...
34 56 26 15 0];
% Cell positions
cellValue = {[1, 4], [2 3]};
% To make it generic, for any number of cell elements with varying size, you can use a for loop
s=0;
for i = 1:numel(cellValue)
cellInd = cellValue{i};
tmp = [];
tmp(1) = a(0+1,cellInd(1)+1);
for j = 2:length(cellInd)
tmp = [tmp a(cellInd(j-1)+1,cellInd(j)+1)];
end
s = sum(tmp) + s;
end
Hope this helps.
Regards,
Sriram
  5 个评论
Sriram Tadavarty
Sriram Tadavarty 2020-3-17
Ya. Please take the latest code in the answer. I had written one value wrong in the matrix and that 10 increase is due to it. If you see the first row and third column of matrix a, it is written as 26 instead of 16.I did correct in it in the answer, take the latest code and check.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Logical 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by