How can I set time for x-axis plot in standard year, month,

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Farshid Daryabor
Farshid Daryabor 2020-3-17
回答： Peter Perkins 2020-4-14
Please find the attached files I want to display time in form of 2017-04, 2017-07, etc. for x-axis. I have trying the following command but is not what I expected, The time reference since 1950-01-01T00: 00: 00Z. eg, 67 + 1950 = 2017
datetick ('x', 'yyyy-mm', 'keeplimits')
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Farshid Daryabor
Farshid Daryabor 2020-3-17
Dear Hiro,
I did follow your command, based on the starttime and endtime,
nc.time_coverage_start = ncchar(''2016-11-02T07:58:00Z'');
nc.time_coverage_end = ncchar(''2018-09-10T12:11:00Z'');
>> t1 = datetime(2016,11,02,07,0,0);
>> t2 = datetime(2018,09,10,12,0,0);
>> tx = t1:t2;
It doesn't work for ploting "pcolor(datenum(tx),-depth,temp);" because "tx(1*678)" is not same size of "depth(143*263)" and "temp(143*263)"
>> pcolor(datenum(tx),-depth,temp);
Error using pcolor (line 59)
Matrix dimensions must agree.
So the only way is to extract the time (in number) from netcdf file which is same size with depth and temp and plot
>> size(time)
1*263
>> size(depth)
143*263
>> size(temp)
143*263
>> pcolor(tx,-depth,temp);
>> datetick('x', 'yyyy-mm', 'keepticks')

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回答（1 个）

Peter Perkins
Peter Perkins 2020-4-14
I have no idea what that mat file is intended to contain. It's one double vector.
In any case, don't use datetick. Just use datetime plotting:
>> t = datetime(2020,1,1:100:1000);
>> y = 1:20;
>> pcolor(t,y,rand(length(y),length(t)))
Normally, you could set the datetime format to what you need, but your case is ... unusual. You'll need to make the tick labels by hand. Get the tick locations, get the offset from 1950 in years and months, and build the labels.
>> ax = gca;
>> t0 = datetime(1950,1,1);
>> ticks = ax.XTick;
>> [y,m] = split(between(t0,ticks),["years","months"])
y =
70 70 71 71 72
m =
0 6 0 6 0
>> xlabs = compose("%04d-%02d",[y',m'])
xlabs =
5×1 string array
"0070-00"
"0070-06"
"0071-00"
"0071-06"
"0072-00"
>> ax.XTickLabel = xlabs;

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