Is there a more efficient way to loop this?

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Or Shem Tov
Or Shem Tov 2020-3-22
评论： Walter Roberson 2020-3-23
Hi guys,
I created a code that extracts certain values from a text headline, each one of these values appear in a different list as follows:
Is there a way to write this code more efficiently without having to go through 5 for loops?
the loops run: 1) 133 times 2) 11 times 3) 81 times 4) 32 times 5) 14 times
Big thanks to anybody that helps!
% Find the issuer
for k = 1:numel(issuersList)
% Check to see which text(s) contain this issuer.
ind = contains(Text, issuersList(k));
% Assign this issue to the correct rows in the output table.
Issuer(ind) = issuersList(k);
end
% Find the action taken by the issuer
for k = 1:numel(ratingActionList)
% Check to see which text(s) contain this issuer.
ind = contains(Text, ratingActionList(k));
% Assign this issue to the correct rows in the output table.
RatingAction(ind) = ratingActionList(k);
end
% Find the new rating
for k = 1:numel(newratingList)
% Check to see which text(s) contain this new rating.
ind = contains(Text, newratingList(k));
% Assign this issue to the correct rows in the output table.
newRating(ind) = newratingList(k);
end
% Find the old rating
for k = 1:numel(oldRatingsList)
% Check to see which text(s) contain this old rating.
ind = contains(Text, oldRatingsList(k));
% Assign this issue to the correct rows in the output table.
oldRating(ind) = oldRatingsList(k);
end
% Find the price target action
for k = 1:numel(ptActionsList)
% Check to see which text(s) contain this price target action.
ind = contains(Text, ptActionsList(k));
% Assign this issue to the correct rows in the output table.
PTAction(ind) = ptActionsList(k);
end
  3 个评论
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Walter Roberson
Walter Roberson 2020-3-23
What is the datatype of Text? What is the datatype of issuersList and other variables that are being searched for?
Or Shem Tov
Or Shem Tov 2020-3-23
They are all string arrays as such:
issuersList =
135×1 string array
"jp morgan"
"citigroup"
"credit suisse"
"oppenheimer"
"morgan stanley"
...
...
...

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回答（1 个）

Walter Roberson
Walter Roberson 2020-3-23
Issuers = regexp(Text, strjoin(issuersList, '|'),'match','once');
  2 个评论
Walter Roberson
Walter Roberson 2020-3-23
Note: this relies on Text being a string array or a cell array of character vectors. In particular if Text is a character vector, then it will only find the first match, including for the case where Text is a character vector with embedded newline characters. If you happen to have a character vector with embedded newlines and want to find the issuer for each line, then use
regexp(Text, '\n', 'split')
before doing the above regexp()

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