Access automatically substructures from loop

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V.D-C
V.D-C 2020-3-24
评论： V.D-C 2020-3-26
Good morning everybody, I hope everything is good for you,
I am working with large structures and I want to automatize some tasks. If we take the structure that I attached to this message, how do I select the nth matrix of the structure ? Without writing "Example.hello" ?
I would like to do the same as when we take the value of a matrix in the nth position ( matrix(n)).
Have a nice day
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Stephen23
Stephen23 2020-3-24
编辑：Stephen23 2020-3-24
Note that field order is NOT fixed and can change. Code that assumes that fields are in a particular order will be fragile.
As Steven Lord wrote, most likely you would be much better off using dynamic fieldnames:

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Steven Lord
Steven Lord 2020-3-24
Rather than depending on the order in which the fields of the struct array are displayed (which can change -- in the following example s and snew contain the same data just in a different order)
s = struct('b',2,'c',3,'a',1)
snew = orderfields(s)
I would use dynamic field names, potentially in conjunction with the fieldnames function, or maybe (if you want to iterate through all the fields of the struct) structfun.
fn = 'b';
b1 = s.(fn)
b2 = snew.(fn)
sSquared = structfun(@(x) x.^2, s)

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