how to average multiple folders with multiple files. I am attaching three folders with two files each. I need a help to find an average of two files from three folders. My code is showing an error"Dot indexing is not supported for variables "

1 次查看（过去 30 天）

显示更早的评论

MS 2020-3-30

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/514070-how-to-average-multiple-folders-with-multiple-files-i-am-attaching-three-folders-with-two-files-eac

评论： MS 2020-4-25

采纳的回答： Ameer Hamza

New folder.zip

在 MATLAB Online 中打开

close all
clear all
D = 'D:\filename\';
S = dir(fullfile(D,'*'));
N = setdiff({S([S.isdir]).name},{'.','..'}); % list of subfolders of D.
for ii = 1:numel(N)
    T = dir(fullfile(D,N{ii},'*')); % improve by specifying the file extension.
    C = {T(~[T.isdir]).name}; % files in subfolder.
    for jj = 1:numel(C)
        F = fullfile(D,N{ii},C{jj})
                fprintf('test%s\n',F);
     S(ii).data = F(:);
    end
end
Y = cat(3,S(:))%this line is wrong
out = mean(Y,3)

3 个评论
显示 1更早的评论隐藏 1更早的评论

MS 2020-3-30

Thanks. I need two files(test_001.txt, test_002,txt) from all three folders(out of six files) finally. let me know if you need further clarifications.

MS 2020-3-30

code through N(here 3 folders) different folders with M(two files here) different.txt files(text001.txt.....text002.txt) with (O rows and P columns). and find the average(text001.txt.....text002.txt)of M different files from the N folders.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Ameer Hamza 2020-3-30

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/514070-how-to-average-multiple-folders-with-multiple-files-i-am-attaching-three-folders-with-two-files-eac#answer_422958

在 MATLAB Online 中打开

Create a script in the same directory where you have folders T1, T2, and T3. Then paste the following code in that script and run it

files = dir('**/*.txt');
data = cell(1, numel(files));
for i=1:numel(files)
    filename = fullfile(files(i).folder, files(i).name);
    data{i} = readmatrix(filename);
end
M = cat(3, data{:});
average_val = mean(M, 3);