Fill a matrix with same values

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Alessandro Masullo
Alessandro Masullo 2012-10-20
Hi! I have a matrix like this:
[ 1 8 9 7 7 4]
[ 0 0 0 0 0 0]
[ 0 0 0 0 0 0]
[ 9 8 6 5 5 1]
[ 0 0 0 0 0 0]
And I want to fill it like this
[ 1 8 9 7 7 4]
[ 1 8 9 7 7 4]
[ 1 8 9 7 7 4]
[ 9 8 6 5 5 1]
[ 9 8 6 5 5 1]
It seems to be very easy, but I cannot realize how to do it. Thank you in advice!

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采纳的回答

Matt J
Matt J 2012-10-20
编辑：Matt J 2012-10-20
Another way,
e=find(any(A,2));
[h,b]=histc(1:size(A,1),[e;inf]);
A=A(e(b),:);
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Matt Fig
Matt Fig 2012-10-20
I knew what you were saying, IA. I agree completely with your main point - a point we have discussed before (but it does bear repeating!).
Cheers!

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更多回答（3 个）

Azzi Abdelmalek
Azzi Abdelmalek 2012-10-20
编辑：Azzi Abdelmalek 2012-10-20
A= [1 8 9 7 7 4
0 0 0 0 0 0
0 0 0 0 0 0
9 8 6 5 5 1
0 0 0 0 0 0]
for k=find(~all(A,2))'
A(k,:)=A(k-1,:)
end
Image Analyst
Image Analyst 2012-10-20
You're all making assumptions of criteria Alex did not give. Making no assumptions whatsoever, this is the fastest way I can think of:
A =[ 1 8 9 7 7 4
1 8 9 7 7 4
1 8 9 7 7 4
9 8 6 5 5 1
9 8 6 5 5 1]
Alessandro Masullo
Alessandro Masullo 2012-10-20
Thank you :D

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