Comparing two binary images: if a pixel is 1 in both images, write a 1 into a new image, otherwise, write a 0.
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Hello everyone,
I have a somewhat noisy image and I would like to reduce or clear the noise.
To do so, I performed and opening. Since I don't want to lose any information of the objects' surface, I think it is easiest, to "compare" the two pictures, the original and the opened one. Meaning, when I have a 1 in the original image and a 1 in the opened image, I want to write a 1 into a third, new image. When I have a 1 in the original picture and a 0 in the opened picture I want to write a 0 in the new, third image. And when there are two 0s, I of couse want a 0 in the new image.
If you click on the link, you see the original image on the left and the opened image in the middle. It should look like a mixture of the first to images with all the surface information...
I tried to multipy the images (result=ImgOpen*ImgOrg), which in my opinion should lead to the desired result (1*1=1; 1*0=0), but the result looks like the image on the right...?!
Do you understand what I mean? It's a little hard to describe that in another language. Sorry!
Thank you! Thymes
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