Finding mean value through every 12 columns of nested doubles in cell

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Hi all,
I'm struggling to adapt previous documentation to my specific case. I have variables, "d" for example below, that are 1x36 cells comprised of nested doubles of the size 771x248-ish (changes size depending on days in a month). Each double is a month's worth of data, and I am trying to find the yearly average over the course of 3 years for one location, so only looking at the values in the first row, all columns (1,:) of the variable (will adapt this to a 30 year case).
The montly average gives me a 1x36 double, which is good.
For the yearly average, I want to obtain a 1x3 double, i.e. one average per year for three years. Again, I am only concerned with the first row, all columns of each nested double in the original cell. Below is what I think the script should look like, but I am only getting one value for the answer:
d_meana = [];
for kk = 1:12:36
d_meana = mean(d{1,kk}(1,:):d{1,kk+11}(1,:));
%will compute for other variables
end
I feel like this should be simple but I'm struggling as a newbie to Matlab. Any tips woudl be greatly appreciated, thank you in advance! Let me know if this is confusing, Itried to word it best I could.

采纳的回答

Geoff Hayes
Geoff Hayes 2020-4-5
Gabrielle - d_meanm is a 1x36 array and you want to find the average of each of the three years, then you could reshape the array so that it is a 12x3 array where each column is a years worth of data. Then just find the average of that to get your 1x3 array
numberOfYears = 3;
d_meana = mean(reshape(d_meanm,12,numberOfYears));
  8 个评论
gd
gd 2020-4-5
Geoff, this works great. Thank you for taking the time to help me, I truly appreciate it. I hope you have a nice rest of your day!

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