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how can we solve this 2 equation?

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Mamad Mamadi
Mamad Mamadi 2020-4-12
评论： Ameer Hamza 2020-4-19
hi dear friends could you plz do me a favor and solve these two equations? the equations are for finding PV cost analysis.
i have two equations
b=53
n=20
1- A=(b+300)+250+100-400
2- P=(A*(1-(1+50)^-n)/50
b is variable b=1:5:50
the system is works for n=20 years. For every b variable i have to find P ;
thanks ;)
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Mamad Mamadi
Mamad Mamadi 2020-4-12
we have to use for loop i think coz b is variable i mean put 5xb to find p1 and put 10xb to find p2 and so on till 50xb
Image Analyst
Image Analyst 2020-4-12
Unless your teacher requires a loop, you don't need one. See Ameer's answer below.

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Ameer Hamza
Ameer Hamza 2020-4-12
编辑：Ameer Hamza 2020-4-12
Both of the following codes are equivalent.
Vectorized:
n = 20;
b = 1:5:50;
A = (b+300)+250+100-400;
P = A*(1-(1+50)^-n)/50;
Result:
P =
Columns 1 through 7
5.0200 5.1200 5.2200 5.3200 5.4200 5.5200 5.6200
Columns 8 through 10
5.7200 5.8200 5.9200
For-loop
n = 20;
b = 1:5:50;
P = zeros(1,numel(b));
for i=1:numel(b)
A = (b(i)+300)+250+100-400;
P(i) = A*(1-(1+50)^-n)/50;
end
Result:
P =
Columns 1 through 7
5.0200 5.1200 5.2200 5.3200 5.4200 5.5200 5.6200
Columns 8 through 10
5.7200 5.8200 5.9200
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Ameer Hamza
Ameer Hamza 2020-4-19
Mamad, In this comment: https://www.mathworks.com/matlabcentral/answers/517357-how-can-we-solve-this-2-equation#comment_827851 I also modified the value of 'b'. But you didn't changed it in your code. Closely see the difference between the value of 'b', I wrote in that comment and your code, and you will find the mistake.

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