I would like to create a matrix using a for loop

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Rodrigo Blas
Rodrigo Blas 2020-4-13
评论： Rodrigo Blas 2020-4-13
function rn=Ljallo_f_q1(T,R,pnh3,po2)
for i=1:3
A=zeros(3,1);
B=zeros(3,1);
C=zeros(3,1);
rn=zeros(3,1);
rn(i)=A(i)/(B(i)*C(i));
A(i)=3.4*10^-8*exp(21700/(R.*T(i)))*pnh3*po2^(.5);
B(i)=1+8*10^-2*exp(4400/(R.*T(i)))*po2^(.5);
C(i)=1+1.6*10^-3*exp(25500/(R.*T(i)))*pnh3;
end
pnh3=.046; %%torr
po2=.068; %%torr
R=62.364*1000; %%cm^3*torr/K*g-mol
T=zeros(3,1);
T(1)=473;
T(2)=673;
T(3)=800;
z=Ljallo_f_q1(T,R,pnh3,po2);
>> Ljallo_s_q1
>> z
z =
0
0
NaN
I would like to create amatrix rn with 3 values(rn(1) rn(2) rn(3)) using a for loop

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采纳的回答

Rik
Rik 2020-4-13
If you had used the debugging tools, you would have noticed that your variables are reset every iteration.
You need to move assignments like A=zeros(3,1) outside of the loop.

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