How do we plot a graph with non available values for y without breaking the continuity?
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INTRO: I have an array M as below:
M=
1 4
2 NaN
3 10
4 NaN
5 NaN
6 15
7 NaN
8 17
9 59
10 NaN
GOAL: I want to plot the second versus the first column as follow:
M=load('M.txt');
h=plot(M(:,1),M(:,2));
PROBLEM: Due to the NaN, it does not plot the gaps correctly and breaks the continuity of the graph.
I wonder if someone could suggest me to some command lines that could fix this issue.
I thank you in advance for your help
Emerson
采纳的回答
Matt Tearle
2012-10-25
You can interpolate to fill the missing values, as Azzi suggests, or simply remove all the NaNs:
idx = ~isnan(M(:,2));
x = M(idx,1);
y = M(idx,2);
plot(x,y,'o-')
If you don't plot markers on the data points, this will look exactly the same as Azzi's solution using interpolation. The difference is whether or not you care about showing which points are actual data values.
1 个评论
Grant
2017-4-11
My problem is that I do care about what is a real value. I want to do what is easy in Excel - have a marker at each real value in my lineplot and have the lines interpolate between points
更多回答（1 个）
Azzi Abdelmalek
2012-10-25
编辑：Azzi Abdelmalek
2012-10-25
Use interpolation
x=M(:,1);
y=M(:,2);
idx=find(~isnan(y))
y=interp1(x(idx),y(idx),x,'linear')
or remove rows containing nan
x=M(:,1);
y=M(:,2);
x(find(isnan(y)))=[]
y(find(isnan(y)))=[]
2 个评论
Matt Tearle
2012-10-25
idx = ~isnan(y);
No need for the find. (Sorry, I love logical indexing!)
Azzi Abdelmalek
2012-10-25
I agree
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