Creating a for loop with coditions
1 次查看(过去 30 天)
显示 更早的评论
Hello,
There are 2 heaters with modes on (m1: heter1 , m2 for heter2) and mode off (m0) and I want to keep the temperature in a room between Vmin=18 °C and Vmax= 22 °C within Tmax=7 hours. and the initial temperature at t=0 is 18 °C. Every time the mode switiched on (m1 or m2) there is a discrete cost paid PiD(m1)= 30 and PiD(m2)= 10 and the cost for staying in this mode is PiC(m1) = 10 and PiC(m2) = 20 while there is no cost for switich off PiD(m0) = PiC(m0) = 0.
The modes parameter (A) are as follows: A(m1)=4/3, A(m2)=2 and A(m0)=-4
For example, the temperature in the room needs 3 hours to reach Vmax using (m1) and 2 hours to reach Vmax using (m2) while just 1 hour to be cooled from Vmax to Vmin.
I am trying to create a loop that generates safe scedules (alpha) with the shape of alpha=<(m0,t0),(m1,t1), (m2,t2),(m3,t3),...(mi-1,ti-1),(mi,ti)>
with the following constraints in order to calculate the the cost of alpha, Pi(alpha)= sumPiD+ sumPiC*ti
% mi Not equal mi+1
% run(alpha)=<v0,v1,v2,v3,...,vi-1,v0)> within T(alpha)=<t0,t1,t2,t3,...,ti-1,ti>
% % Vmin <= V(i) <= Vmax
% 0 < ti <=Tmax
% sum(ti)= Tmax
%
% V(t0) = V(0) = V0 = 18
% V(i) not equal V(i+1), either greater or lower depending on the mode.
% V(i)= V(i-1)+(A(m i)*[((sum(from i=0 to t(i)) ti))-(sum(from i=0 to t(i-1)) ti))]
% V(t) = V(i-1)+A(m i)*(t-(sum(from i=1 to t(i-1)) ti)) , the temperature at any point of time
% t = (V(i-1)/A(m i))-t(i-1)
Can someone help me please with creating a foor loop that generates 50 safe shedules (alpha), and schedule that does not meet the previous features is considered irrelevnt. To calculate the cost Pi(alpha). Here is my units definition
%------------------------------------------------------------------------%
clear variables;
close all;
clc;
%------------------------------------------------------------------------%%
%% Define units
%---------------------------------------------------------------------------------------------------------------------%
Vmax = 22; % The highest temperature we can reach [°C]
Vmin = 18; % The lowest temperature we can reach [°C]
V0 = 18; % Inetial temperature at time = 0
K = 2; % Number of heaters
Tmax = 7; % Total time [h]
PiC = [10 20]; % Continuous cost [$/h]
PiD = [30 10]; % Discrete cost [$]
A = [4/3 2]; % Heating parameters for mode 1,2 [°C/h]
A0 = -4; % Cooling parameters for mode 0, when the heaters are off [°C/h]
%---------------------------------------------------------------------------------------------------------------------%
3 个评论
回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!