Find max and min values, seperated by max or min

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FV
FV 2020-4-20
评论： KSSV 2020-4-20
I have a large set of numbers and need to find two minimum values and two maximum values. However it shouldn't just be the two absolute max and min values they need to be seperated by a max or min value. So max,min,max,min.

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KSSV
KSSV 2020-4-20
编辑：KSSV 2020-4-20
Let A be your array.
[val1,idx1] = max(A) ;
A(idx1) = NaN ;
[val2,idx2] = max(A) ;
if idx1 > idx2
[val3,idx3] = min(A(idx2:idx1)) ;
else
[val3,idx3] = min(A(idx1:idx2)) ;
end
[val4,idx4] = min(A(idx2:end)) ;
Also read about findpeaks. Also you can sort array and get it.
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FV
FV 2020-4-20
no, it won't be any value between them, that's the problem. I want to exlude max values that is beside each other.
I made an example, so if A=[1;3;1.2;1.2;0.7;0.6;0.61;1;4;7;1.2;0.5]; The two max values is beside each other. I don't want that. So instead of 7 and 4 is max I want 7 and 3.
I also want the code to work if they are not beside each other. Just if the two values is next to each other I want to find the next value.
KSSV
KSSV 2020-4-20
clc; clear all ;
A=[1;3;1.2;1.2;0.7;0.6;0.61;1;4;7;1.2;0.5];
B = A ;
[val1,idx1] = max(A) ;
A(idx1) = NaN ;
[val2,idx2] = max(A) ;
while (abs(idx1-idx2)==1)
A(idx2) = NaN ;
[val2,idx2] = max(A) ;
end
if idx1 > idx2
[val3,idx3] = min(A(idx2:idx1)) ;
else
[val3,idx3] = min(A(idx1:idx2)) ;
end
[val4,idx4] = min(A(idx2:end)) ;

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