solving coupled differential system
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Hello. I am trying to solve two coupled differential equation as below:
m1x"+m2ry"=-k1(2x1-x2-x0)
m2x"+Ay"=-k2x1+Ky-f
Note: m1,m2,k1,k2,x2,x0,A,k2,K,f are known
thanks alot
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John D'Errico
2020-4-25
编辑:John D'Errico
2020-4-25
Why was it necessaryu to ask this question twice? I've closed the other one you asked.
回答(1 个)
Radu Trimbitas
2020-4-25
Dear Saman,
If set x=u(1), x'=u(2), y=u(3), y'=u(4) and
M=[1,0,0,0; 0, m1,0,m2; 0,0,1,0; 0, m2,0,A], then the system becomes
[u(2); -k1*(2*x1-x2-x0); u(4);-k2*x1+K*u(3)-f];
M could be seen as a mass matrix and can be introduced using option Mass in odeset function, see the attachment.
另请参阅
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