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How to use 2D logical mask on an image without for loop?

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xiaojuezi
xiaojuezi 2020-4-28
评论： KSSV 2020-4-28
I have two image matrices A and B with size 512 x 512 x 3, and a logical mask of size 512 x 512. For each position with true value in the mask, I want to set A's value to B's. Currently I only know the for loop solution:
for y = 1 : height
for x = 1 : width
if mask(y,x)
A(y,x,:) = B(y,x,:)
end
end
end
Is there a way to avoid the for loop?

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回答（1 个）

KSSV
KSSV 2020-4-28
B = zeros(512,512,3) ;
for i = 1:3
T1 = B(:,:,1) ;
T2 = A(:,:,i) ;
T1(idx) = T2(idx) ;
B(:,:,i) = T1 ;
end
  2 个评论
xiaojuezi
xiaojuezi 2020-4-28
Does this solution set B's value as A's instead of other way round as in the for loop?
KSSV
KSSV 2020-4-28
It sets A's values to B. You can change it, if you want the other way.

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