How to stop a rand function from getting the same result in a for loop

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Cooper Mathews
Cooper Mathews 2020-5-2
评论： Mehmed Saad 2020-5-2
Hey guys basic question.
I have this code here and i want to print the card deck in a random order:
for x = 1:52
y = randi([1 52]);
if y == 1
fprintf('%s\n','Spade Ace')
elseif y == 2
fprintf('%s\n','Spade 2')
(continues through the whole card deck 1-52)
elseif y == 51
fprintf('%s\n','Clubs Queen')
else
fprintf('%s\n','Clubs King')
end
end
Is there a way I can stop the rand function from comming up with the same number?

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回答（2 个）

Walter Roberson
Walter Roberson 2020-5-2
cards = {'Spade Ace', 'Spade 2', 'Spade 3' up to 'Clubs Queen', 'Clubs King'};
x = randperm(52);
fprintf('%s\n', cards{x});
No loop needed. rand() not explicitly used (it is used inside of randperm)
Mehmed Saad
Mehmed Saad 2020-5-2
编辑：Mehmed Saad 2020-5-2
I dont know how to stop rand function from comming up with same number but there is a way you can do that by indexing and removing numbers.
z = 1:52;
x = zeros(1,52);
for i =1:52
y = randi([1 length(z)]);%
x(i) = z(y);
z(y) = [];
end
This will generate random number without repeating them
I stored all the values in x, to check if they are right type following in command window
sort(x)
it will be from 1:52 without any repeatition

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