I only have the mean value and standard deviation value, how do I make a histogram with this?

Question

Aasiya Syed 2020-5-3

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/522588-i-only-have-the-mean-value-and-standard-deviation-value-how-do-i-make-a-histogram-with-this

回答： Walter Roberson 2020-5-3

My mean is -30.10 and my standard deviation is 7.79

My count is going to be a maximum limit of 150.

How would I construct a histogram with just this info?

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

Walter Roberson 2020-5-3

You need to know the distribution involved. Also if you are talking about maximum counts then you need to specify a bin size.

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Mathias Andersen 2020-5-3

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/522588-i-only-have-the-mean-value-and-standard-deviation-value-how-do-i-make-a-histogram-with-this#answer_429904

在 MATLAB Online 中打开

This should do the trick.

x = 7.79*randn(150,1)-30.1;
histogram(x,'Normalization','pdf')

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

Answer 2

Walter Roberson 2020-5-3

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/522588-i-only-have-the-mean-value-and-standard-deviation-value-how-do-i-make-a-histogram-with-this#answer_429912

https://www.mathworks.com/help/stats/normcdf.html

Use normcdf on two values representing the edges of the bin that you wish to have the maximum count of 350. diff() to find the probability associated with the bin. ceil() 350 divided by that probability. The result is the number of samples that you need to simulate so that the maximum expected count would be 350.

Now you can use normcdf on a vector of bin edges, diff, multiply by the sample size, and that gives the counts for the bins. Or you can generate the appropriate number of random points calculated and histogram.