I am almost a beginner in MATLAB. Dear all, I want to make code using FOR because node 1 to 4 has same value, and 5 to 8 also has same value.THANK YOU

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DEWDROP
DEWDROP 2020-5-3
评论： DEWDROP 2020-5-5
[node1]=[0 0 0 1 1 1];
[node2]=[0 0 0 1 1 1];
[node3]=[0 0 0 1 1 1];
[node4]=[0 0 0 1 1 1];
[node5]=[1 1 1 1 1 1];
[node6]=[1 1 1 1 1 1];
[node7]=[1 1 1 1 1 1];
[node8]=[1 1 1 1 1 1];

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Image Analyst
Image Analyst 2020-5-3
OK, your code looks like it does that, but without a for loop, which is not needed unless you want a 2-D array rather than individual variables. Nodes 1 through 4 have one value (array), which is the same for all 4. And nodes 5-8 also have the same value, but different than nodes 1-4. So what's the problem? Do you have a question? As it is, this is just an announcement.
If you wanted a for loop, you could do
allNodes = ones(8, 6); % Initialize to all ones
for row = 1 : 4
allNodes(row, :) = [0 0 0 1 1 1];
end
At least that's one way to use a for loop. There are others.
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Image Analyst
Image Analyst 2020-5-4
You can append this loop if you want to print them out:
for row = 1 : size(allNodes, 1)
fprintf('node %d = [', row);
fprintf('%d ', allNodes(row, :));
fprintf(']\n');
end
It displays the output (in the command window of course):
node 1 = [0 0 0 1 1 1 ]
node 2 = [0 0 0 1 1 1 ]
node 3 = [0 0 0 1 1 1 ]
node 4 = [0 0 0 1 1 1 ]
node 5 = [1 1 1 1 1 1 ]
node 6 = [1 1 1 1 1 1 ]
node 7 = [1 1 1 1 1 1 ]
node 8 = [1 1 1 1 1 1 ]
exactly like you wanted.

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