How can I gather all the values from a loop into an array?

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Hi,
I was wondering how can I gather all the values into an array because I need to plot the answer later. This is part of the code I am writing:
for i=x0:h1:xx-h1 % Where h1 is the step size
y1=y1+dy(i,y1)*h1;
i=i+h1;
end
If someone knows, please let me know! Thanks!
  3 个评论
Raquel Terrer van Gool
This is the full code. When I try to do that, I get an error saying that the array indices must be positive and logical.
yi=@(x)exp(1/3*x.^3-1.2*x);
dy=@(x,y)y*x.^2-1.2*y;
x0=0; xx=2; y1=1; y2=1;
xp=[0:0.01:2];
h1=0.25;
h2=0.1;
for i=x0:h1:xx-h1 % Where h1 is the step size
y1=y1+dy(i,y1)*h1;
i=i+h1;
end
for i=x0:h2:xx-h2 % Where h2 is the step size
y2=y2+dy(i,y2)*h2;
i=i+h2;
end

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采纳的回答

Star Strider
Star Strider 2020-5-5
编辑:Star Strider 2020-5-5
Knowing only what you posted, I would do something like this:
i=x0:h1:xx-h1; % Where h1 is the step size
y1v = zeros(size(i)); % Preallocate
for k = 1:numel(i)
y1=y1+dy(i,y1(k))*h1;
y1v(k) = y1;
end
That stores the existing values of ‘y1’ as vector ‘y1v’ so it stores the values while not otherwise disrupting the code. The ‘i’ vector is now separate, so to plot them later, something like this would likely work:
figure
plot(i, y1v)
grid
I did not test this, however it should work.
EDIT —
With the full code (not available when I first posted this), it changes to:
yi=@(x)exp(1/3*x.^3-1.2*x);
dy=@(x,y)y*x.^2-1.2*y;
x0=0; xx=2; y1=1; y2=1;
xp=[0:0.01:2];
h1=0.25;
h2=0.1;
i1=x0:h1:xx-h1; % Where h1 is the step size
y1v = zeros(size(i1)); % Preallocate
for k = 1:numel(i1)
y1=y1+dy(i1(k),y1)*h1;
y1v(k) = y1;
end
i2=x0:h2:xx-h2; % Where h2 is the step size
y2v = zeros(size(i2)); % Preallocate
for k = 1:numel(i1)
y2=y2+dy(i2(k),y2)*h2;
y2v(k) = y2;
end
figure
plot(i1, y1v, i2, y2v)
grid
This runs without error, and appears to produce the correct result.
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