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minimum of a 3D matrix

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Qian
Qian 2012-10-31
M=rand(2,2,3)
[minM idx] = min(M(:));
[n m t] = ind2sub(size(M),idx)
minM
M(n,m,t)
I know this will give the minimum of the M matrix.
However, I want minimum value only for each M(:,:,i) part.
Is there anyway to do that?
Thanks in advance!

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2012-10-31
编辑：Azzi Abdelmalek 2012-10-31
M=rand(2,2,3);
out=min(reshape(min(M),size(M,2),[],1))'
or
out=arrayfun(@(x) min(min(M(:,:,x))),1:size(M,3))'
If you want to get the corresponding index
M=rand(6,4,5);
[n,m,p]=size(M)
[c,idx]=min(M)
[c1,idx2]=min(c)
idx1=arrayfun(@(x) idx(1,idx2(1,1,x),x),(1:p)')
v=[c1(:) idx1(:) idx2(:) (1:p)' ]

更多回答（1 个）

Image Analyst
Image Analyst 2012-10-31
Try this:
minOfPlane = min(min(M(:,:, t)))
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Andrei Bobrov
Andrei Bobrov 2012-10-31
[v, i1] = min(reshape(M,[],size(M,3)));
min_idx_m_n_t = [rem(i1-1,size(M,1))+1; ceil(i1/size(M,1)); 1:size(M,3)]';
Walter Roberson
Walter Roberson 2012-10-31
Ah yes, the 0:2 I used should be 0:size(M,3)-1

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