Conversion of argument 2 from "real_T [2]" to "const int []" not possible;

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Bhushan Ravindra Attarde
评论： Geoff Hayes 2020-5-11
Hi I am trying to call my function in coder.ceval method. The function declaration of my code in header file is :
STATE_SPACE_EQN_DLL_EXPORT extern void State_Space_Eqn(const double a_data[],
const int a_size[2], const double b_data[], const int b_size[2], const double
c_data[], const int c_size[2], const double d_data[], const int d_size[2],
double x_data[], int x_size[2], const double u_data[], const int u_size[2],
double out_data[], int out_size[2]);
And I am calling it by using coder.ceval method as follows:
function output = State_Space_Eqn_X(A,B,C,D,X,U)
% Running in generated code, call library function.
coder.cinclude('State_Space_Eqn.h');
output = coder.nullcopy(U);
a = size(A);
b = size(B);
c = size(C);
d = size(D);
x = size(X);
u = size(U);
out = size(output);
coder.ceval('State_Space_Eqn', coder.rref(A),a,coder.rref(B),b,coder.rref(C),c,coder.rref(D),d,coder.rref(X),x,coder.rref(U),u,coder.wref(output),out);
end
When I call this function in Matlab function block on Simulink, I am getting this error:
Conversion of argument 2 from "real_T [2]" to "const int []" not possible;
The types referenced are not linked; the conversion requires a reinterpret_cast operator or a type conversion in C or function format.
Can someone please help me in this code?

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采纳的回答

Geoff Hayes
Geoff Hayes 2020-5-9
Bhushan - I don't use Simulink so don't know for sure if this will work but if the error message is telling you that it can't convert from a real (double) to an integer, then maybe you have to do the conversion yourself. Remember that the class type of the array returned by size is still a double so try to do the conversion there
function output = State_Space_Eqn_X(A,B,C,D,X,U)
% Running in generated code, call library function.
coder.cinclude('State_Space_Eqn.h');
output = coder.nullcopy(U);
a = int32(size(A));
b = int32(size(B));
c = int32(size(C));
d = int32(size(D));
x = int32(size(X));
u = int32(size(U));
out = int32(size(output));
coder.ceval('State_Space_Eqn', coder.rref(A),a,coder.rref(B),b,coder.rref(C),c,coder.rref(D),d,coder.rref(X),x,coder.rref(U),u,coder.wref(output),out);
end
I'm assuming that an int32 is equivalent in C to an int.
  2 个评论
Bhushan Ravindra Attarde
Bhushan Ravindra Attarde 2020-5-9
Yes. This is working perfectly fine for me. I tried using int64 but was showing same error. Can you please explain why it was not working with int64?
Thank you for your valuable time.
Geoff Hayes
Geoff Hayes 2020-5-11
Bhushan - in C/C++, an integer, int, is typically 32 bits so that is why you need to convert your size dimensions from the (probably) 64-bit doubles to a 32-bit integer via int32. When you use int64, this will convert the doubles to 64-bit integers which is not the expected/required 32 bits as given in the function signature.

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