find repeated columns of a matrix

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Hello,
Consider a 8x100 matrix.
It consists of 5 8x1 columns that are repeated randomly, namely the col1,...,col5.
How can I find the indexes of the columns that contain the col1?
Thank you.
Pavlos

采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2012-11-1
A=repmat(rand(8,5),1,100/5)
A=A(:,randperm(100)) % your matrix
col1=A(:,1)
idx=find(~any(bsxfun(@minus, A,col1)))

更多回答(1 个)

Matt J
Matt J 2012-11-1
编辑:Matt J 2012-11-1
indices=find(ismember(yourmatrix.',col1.','rows'))
  4 个评论
Matt J
Matt J 2012-11-1
Hah! I hit 500 points because of your upvote. Thanks!

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