how to convert the cell to matrix

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Shehab Tarek
Shehab Tarek 2020-5-15
编辑： Stephen23 2020-5-16
i have cell as shown in picture
and i want to convert it to Array then flip it to be like
array=
00
10
010
110
111
EDIT: Shehab Tarek's "Answer" moved here:
%YY
%[0,0]
%[0,1]
%[0,1,0]
%[1,1,0]
%[0,1,1]
%[1,1,1]
matrix=[];
lenght=[];
for i=1:6
[~,c]=size(YY{i}); % the cell matrix
length=[length c]; % length of each element in cell
s=YY{i}; % variable
matrix=[matrix s];
end
length=length';
although you can show the code in file un.m
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Shehab Tarek
Shehab Tarek 2020-5-15
i know that the vector lenght is not the same .then i have the length of each array in the cell for example
length=[2,2,3,3,3];
martix=0010010010110111;
i want to diveded the matrix to sub element depend on the length
to be
matrix =[00,10,010,110,111];
Ameer Hamza
Ameer Hamza 2020-5-15
Can you share the code which is used to generate the matrix? You cannot represent 0010010010110111 in floating-point format. Is it a character array?

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回答（1 个）

dpb
dpb 2020-5-16
Presuming the input is a cell array, m...
>> cellfun(@(s) sprintf('%d',fliplr(s)),m,'UniformOutput',false)
ans =
6×1 cell array
{'00' }
{'01' }
{'010'}
{'011'}
{'110'}
{'111'}
>>
NB: the sample output has only five elements of the six in the input array...

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