How do I plot this simple function in matlab

1 次查看(过去 30 天)
I have a function f(x) = +i x>0;
= 1 x=0;
= -i x<0 ;
I am confused because of the existence of the complex number. Suppose I want to take the fourier transform of this function. I do y=fft(f(x)); plot(x,real(y)); Is this right?

采纳的回答

Wayne King
Wayne King 2012-11-2
Did you simply want to plot that complex-valued function of a real variable, f(x), you can do that with stem3
x= -50:50;
y = zeros(size(x));
y(x<0) = -1i;
y(x>0) = 1i;
y(x==0) = 1;
stem3(x,real(y),imag(y))
xlabel('x'); ylabel('Re(f(x))'); zlabel('Imag(f(x))');
  1 个评论
Poonam
Poonam 2012-11-2
Hi,
I loved the way you plotted it. Thank you. I would like to know if I could combine the 3 conditions of y and put into one equation. I actually want to multiply this with another function and take the FFT of it? How could I do that?

请先登录,再进行评论。

更多回答(1 个)

Azzi Abdelmalek
Azzi Abdelmalek 2012-11-2
编辑:Azzi Abdelmalek 2012-11-2
x=rand(100,1) % eg
y=fft(x)
plot(abs(y))
why real(y)?

类别

Help CenterFile Exchange 中查找有关 Line Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by