How to give an array with dynamic size as a paramter to fucntion?

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Gözde Üstün
Gözde Üstün 2020-5-17
评论： Gözde Üstün 2020-5-17
Hey!
I have a problem. I want to use an array with dynamic size. I mean user can define a size for an array and each element of this array is also an another array:
If user wants an array with a 5 element, the user will wuse the function like that
[A,B,C,D,E]=trying(d)
and each of these A,B,C,D,E will be an array like
A=zeros(d,d,2,d);
B=zeros(d,d,2,d);
C=zeros(d,d,2,d);
D=zeros(d,d,2,d);
E=zeros(d,d,2,d);
or if user wants an array with 2 element, the user can write that:
[A,B]=trying(d)
and the fucntion should do that:
A=zeros(d,d,2,d);
B=zeros(d,d,2,d);
What I mean is that the parameter will be an array with a dynamic size
How can I do that in MATLAB ? I have to use MATLAB and I am very new in MATLAB

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采纳的回答

Ameer Hamza
Ameer Hamza 2020-5-17
  4 个评论
显示 2更早的评论
Stephen23
Stephen23 2020-5-17
"I know eval is not a good function ... because in this case eval is the best"
I very much doubt that eval is "the best" for this task.
Ameer Hamza already showed a much better solution using repmat, here are some other much better ways:
function varargout = trying(d)
varargout = cell(1,max(1,nargout));
varargout(:) = {zeros(d,d,2,d)};
end
function varargout = trying(d)
for k = max(1,nargout)):-1:1
varargout{k} = zeros(d,d,2,d);
end
end
Much simpler, neater, and more efficient using basic MATLAB arrays and indexing.
eval is what beginners use to force themselves into writing slow, complex, inefficient code.

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