Presenting this results in a tabulated form?

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Otto
Otto 2012-11-4
回答： Dianne Dampil 2014-2-25
Hi All,
I've written a code. Now, I want to tabulate this results using fprintf in a format that;
1'st column corresponds i(i.e. iteration number 1,2,3...), 2'st column corresponds xl, 3 column xu, 4'th f(xl), 5'th f(xu), 6'th xr, 7'th f(xr) and 8'th column corresponds ea. And also xl,xu,f(xl),f(xu) and f(xr) should have 7 digits after decimal point, xr must have 10 digits after decimal point. and finally ea must include 4 digits after decimal point.
Here is the code;
f=@(x)x^10-1
xl=0
xu=1.3
xr = xu;
es=0.01
fl=f(xl)
fu=f(xu)
iter=0;
iu = 0; il = 0;
while (1)
xrold = xr;
xr = xu - fu*(xl-xu)/(fl-fu);
fr = f(xr);
iter=iter+1;
if xr<0
elseif xr>0
ea=abs((xr-xrold)/xr)*100
end
test = fl*fr
if test<0
xu = xr
fu = f(xu)
iu = 0
il = il+1
if il>=2
fl=fl/2
end
elseif test>0
xl=xr
fl=f(xl)
il=0
iu=iu+1
if iu>=2
fu=fu/2
end
else
ea=0
end
if ea<es
break
end
end
ModFalsePos=xr
I've tried something but find out that some of the variables include only the last value of calculations. for example xl,xr, iter, but i want to present them in a listed form.
I'll appreciate for any help.
Thanks already for your interest!

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采纳的回答

Matt Fig
Matt Fig 2012-11-5
编辑：Matt Fig 2012-11-5
Holy lack of semi-colons! Try this:
home
f=@(x)x^10-1;
xl=0;
xu=1.3;
xr = xu;
es=0.01;
fl=f(xl);
fu=f(xu);
iter=0;
iu = 0;
il = 0;
fprintf('\n\n%10s%10s%10s%10s%10s%10s%10s%10s\n',...
'iter','xl','xu','f(xl)','f(xu)','xr','f(xr)','ea')
fprintf([' ',repmat('-',1,74),'\n'])
while 1
xrold = xr;
xr = xu - fu*(xl-xu)/(fl-fu);
fr = f(xr);
iter=iter+1;
if xr<0
elseif xr>0
ea=abs((xr-xrold)/xr)*100;
end
test = fl*fr;
if test<0
xu = xr;
fu = f(xu);
iu = 0;
il = il+1;
if il>=2
fl=fl/2;
end
elseif test>0
xl=xr;
fl=f(xl);
il=0;
iu=iu+1;
if iu>=2
fu=fu/2;
end
else
ea=0;
end
if ea<es
break
end
fprintf('%10.2i%10.2f%10.2f%10.2f%10.2f%10.2f%10.2f%10.2f\n',...
iter,xl,xu,f(xl),f(xu),xr,f(xr),ea)
end
fprintf('\n\n')
ModFalsePos=xr;
  1 个评论
Otto
Otto 2012-11-5
Hi Matt,
I've worked on the code which you sent a bit and I also have a final question. I want to display also the very first, the initial values (00'th values) and the last values (12'th iteration) too. how can I do this? Here is the new code;
home
f=@(x)x^10-1;
xl=0;
xu=1.3;
xr = xu;
es=0.01;
fl=f(xl);
fu=f(xu);
iter=0;
iu = 0;
il = 0;
fprintf('\n\n%10s\t%10s\t%10s\t%10s\t%10s\t%10s\t\t%10s\t%10s\n',...
'iter','xl','xu','f(xl)','f(xu)','xr','f(xr)','ea')
fprintf([' ',repmat('-',1,92),'\n'])
while 1
xrold = xr;
xr = xu - fu*(xl-xu)/(fl-fu);
fr = f(xr);
iter=iter+1;
if xr<0
elseif xr>0
ea=abs((xr-xrold)/xr)*100;
end
test = fl*fr;
if test<0
xu = xr;
fu = f(xu);
iu = 0;
il = il+1;
if il>=2
fl=fl/2;
end
elseif test>0
xl=xr;
fl=f(xl);
il=0;
iu=iu+1;
if iu>=2
fu=fu/2;
end
else
ea=0;
end
if ea<es
break
end
fprintf('%10.2i\t%10.7f\t%10.7f\t%10.7f\t%10.7f\t%10.10f\t%10.7f\t%10.4f\t\n',...
iter,xl,xu,f(xl),f(xu),xr,f(xr),ea)
end
fprintf('\n\n')
ModFalsePos=xr;
Thank you so much for your help!

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更多回答（1 个）

Dianne Dampil
Dianne Dampil 2014-2-25
can someone help me tabulate this?

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