The naming model that you suggest is not really the best way to name your variables. Consider the following:
Get the list of files that end with ".xls",
files = dir('*.xls')
For each element in "files", read the Excel data of that file and define structure of x, y, & z
for i = 1:numel(files)
data = xlsread(files(i).name);
x.(files(i).name) = data(:,1);
y.(files(i).name) = data(:,2);
z.(files(i).name) = data(:,3);
end
Sorry I didn't get a chance to test this, so I hope this works for what you are trying to do. Also, if the files are sequentially numbered and the number of rows are the same in each file, you may want to consider storing the data in standard arrays (i.e. x(:,i)), rather than in structures.
