Is there a faster way to implement a FIFO (queue) ?
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Hi, I was wondering if somebody could comment on my use of array indexing. I have a recursive function which uses some initial conditions passed in. I use it in the following manner.
ic = [x_i ic(1:end-1)];
ic is a long vector. x_i is a double.
This line seems to be taking a lot of execution time, about 50% of the total time Matlab spends in this function (using Profiler). The rest of the code is set of vectorized computations; I believe they are as fast as they can be.
I made one small adjustment and it made it a bit faster.
ic(2:end) = ic(1:end-1);
ic(1) = x_i;
This improved the execution time and these two lines take 40% of the total execution time of the function.
Could anybody suggest any better way of implementing this FIFO array.
Thanks for your time and comments.
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Brian Harris
2022-4-12
编辑:Brian Harris
2022-4-12
See this answer: Fast FIFO Array. The circleshift one (which is really just to realign the last answer) is fast because its just a moving pointer "ic=mod(i,Nmax+i)" so doens't move anything. Its really just a circular buffer.
回答(1 个)
Bruno Luong
2022-4-12
编辑:Bruno Luong
2022-4-12
If you don't need to retreive the whole FIFO in order, but read and write element by element, then the best way is NOT rearrange the FIFO buffer
FIFO=nan(1,1000);
n = length(FIFO);
nbreadwrte = 1e6;
% Use index to mark place of the oldest element
tic
for i=1:nbreadwrte
% readcell
oldout = FIFO(mod(i-1,n)+1);
newin = rand(1);
% write, recent MATLAB do inplace change of internal data
FIFO(mod(i-1,n)+1) = newin;
end
toc
tic
for i=1:nbreadwrte
% readcell
oldout = FIFO(1);
newin = rand(1);
% write
FIFO = [newin FIFO(1:end-1)];
end
toc
for i=1:nbreadwrte
% readcell
oldout = FIFO(1);
newin = rand(1);
% write
FIFO(2:end) = FIFO(1:end-1);
FIFO(1) = newin;
end
toc
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