find x intercepts numerically
4 次查看(过去 30 天)
显示 更早的评论
I'm trying to find a quick way of returning the index of all the places where an [x,y] data set crosses the x axis.
I've tried: zci = @(v) find(v(:).*circshift(v(:), [-1 0]) <= 0)
But it isn't returning all the zeros and also always returns the last value in my dataset as a zero even though it isn't. I'm testing with a third order polynomial and can only get my code to work if it have only one root.
Thanks!
0 个评论
采纳的回答
Ameer Hamza
2020-5-25
编辑:Ameer Hamza
2020-5-25
Try this
f = @(x) find(diff(sign(x)));
Example
>> x = [1 2 -1 -2 -1 2 3 1 -2 -3 -2 1];
>> f(x)
ans =
2 5 8 11
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Axis Labels 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!