Removing NaN in all the columns from matrix A to produce matrix B

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JL
JL 2020-5-28
评论： JL 2020-5-28
I have matrix A
A = [1 NaN 55 NaN 14 NaN 1 NaN 1 NaN 1
2 NaN 55 NaN 14 NaN 1 NaN 1 NaN 1
3 NaN 55 NaN 14 NaN 1 NaN 1 NaN 1
4 NaN 35 NaN 14 NaN 1 NaN 1 NaN 1];
Remove all the NaN
B = [1 55 14 1 1 1
2 55 14 1 1 1
3 55 14 1 1 1
4 35 14 1 1 1];

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采纳的回答

Fangjun Jiang
Fangjun Jiang 2020-5-28
编辑：Fangjun Jiang 2020-5-28
index=any(isnan(A));
B=A(:,~index)

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