How to separate an array into 3

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gmltn1212
gmltn1212 2020-5-28
Hi I am trying to divide one array into 3 arrays
let's say A = [11 22 33 44 55 66 77 88 99]
I want to divide A like this:
B = [11 33 55 77]
C = [22 44 66 88]
D = [99]
This is just an example...Could you come up some idea for this?

回答(2 个)

Stephen23
Stephen23 2020-5-29
>> A = [11,22,33,44,55,66,77,88,99];
>> B = A(1:2:end-1)
B = 11 33 55 77
>> C = A(2:2:end-1)
C = 22 44 66 88
>> D = A(end)
D = 99

Brent Kostich
Brent Kostich 2020-5-28
A simple way is by indexing, like so:
A = [11 22 33 44 55 66 77 88 99];
B = A([1, 3, 5, 7]);
C = A([2, 4, 6, 8]);
D = A(9);
If you are looking for a more general solution than explicit indexing, then you will have to provide more parameters for your problem.
  2 个评论
gmltn1212
gmltn1212 2020-5-28
Thank you for solution.
But what if A always contains odd number of elements and B and C should take every other elements (explained above) and D is required to take the last element of the array?
for D i figured out the function: lastDigit = A(end);
Could you give me something like this?
Brent Kostich
Brent Kostich 2020-5-29
If you wanted to filter by even and odd, then you should have specified that in your question. That operation is not difficult though, see Stephen Cobeldick's answer.

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