Given matrices XX and YY of sizes 3X3, how can I generate the following matrix: [XX(1,1) YY(1,1); XX(1,2) YY(1,2)... ?

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Gil
Gil 2012-11-15
Given matrices XX and YY of sizes 3X3, how can I generate the following matrix:
[XX(1,1) YY(1,1); XX(1,2) YY(1,2);XX(1,3) YY(1,3); XX(2,1) YY(2,1); XX(2,2) YY(2,2); XX(2,3) YY(2,3); XX(3,1) YY(3,1); XX(3,2) YY(3,2); XX(3,3) YY(3,3)]
I mean of course, without writing it explicitly and without loops.
Thanks!!

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采纳的回答

C.J. Harris
C.J. Harris 2012-11-15
or:
XX = magic(3);
YY = eye(3);
XX_trans = transpose(XX);
YY_trans = transpose(YY);
out = [XX_trans(:) YY_trans(:)];

更多回答（2 个）

Matt Fig
Matt Fig 2012-11-15
编辑：Matt Fig 2012-11-15
For example:
XX = magic(3);
YY = cumsum(ones(3));
% Your requested matrix.
ZZ = [reshape(XX.',[],1) reshape(YY.',[],1)]
C.J. Harris
C.J. Harris 2012-11-15
编辑：C.J. Harris 2012-11-15
This is one way of doing it - expanding on my answer to your previous question:
XX = magic(3);
YY = eye(3);
out = unique(nchoosek([1:3, 1:3], 2), 'rows');
XX_Array = arrayfun(@(x)[(XX(out(x,1),out(x,2)))], 1:size(out,1))';
YY_Array = arrayfun(@(x)[(YY(out(x,1),out(x,2)))], 1:size(out,1))';
combArray = [XX_Array YY_Array];

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