Create a loop which fills numbers 1-7 into matrix until matrix length reached
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This is gonna be an easy fix I'm sure. I have a matrix(21,4), and in colum 2 I would like to insert the numbers 1-7 so that they repeat until the end of the column (which is 21 rows long). So I probably need a loop of some sort I'm guessing.
Tried this, which obviously doesn't work:
for rowNumber = 1:21
for oneToSeven = 1:7
imageinformation(rowNumber, 2) = oneToSeven;
end
end
采纳的回答
Andrei Bobrov
2012-11-17
A - your matrix with size <21 x 4 >
A(:,2) = rem((0:size(A,1)-1)',7)+1;
更多回答（1 个）
Matt Fig
2012-11-18
Andrei has shown you a preferred method. However, in answer to your original question, here is one way to solve it with a double loop (as you were attempting to do):
A = zeros(21,4); % Starting matrix.
for ii = 1:3
for jj = 1:7
A((ii-1)*7 + jj,2) = jj;
end
end
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