how to create incrementing arrays from each row of a matrix?

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Javier Cabello 2020-6-2

评论： Javier Cabello 2020-6-3

I have a big table starts like this

A B

33 17

30 -4

26 14

25 14

I would like to get a new array containing the increments of the form (B:A) from each of the rows.

For instance (table.B(1):table.A(1)), (table.B(2):tableA(2)) and so on.

Is there a simple way to do this? Is a loop necessary?

Thank you

madhan ravi 2020-6-2

编辑：madhan ravi 2020-6-2

indices = arrayfun(@(x) Table.B(x):Table.A(x),1:size(B,1),'un',0);

madhan ravi 2020-6-2

Note: Don’t name a variable named table you will shadow the inbuilt function table(...)

Javier Cabello 2020-6-3

Awesome! thanks for your help. Also thanks for noting the conflict with the function table, I just used it as a name here for my example.

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