how to create incrementing arrays from each row of a matrix?

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Javier Cabello
Javier Cabello 2020-6-2
评论： Javier Cabello 2020-6-3
I have a big table starts like this
A B
33 17
30 -4
26 14
25 14
I would like to get a new array containing the increments of the form (B:A) from each of the rows.
For instance (table.B(1):table.A(1)), (table.B(2):tableA(2)) and so on.
Is there a simple way to do this? Is a loop necessary?
Thank you

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madhan ravi
madhan ravi 2020-6-2
编辑：madhan ravi 2020-6-2
indices = arrayfun(@(x) Table.B(x):Table.A(x),1:size(B,1),'un',0);
  2 个评论
madhan ravi
madhan ravi 2020-6-2
Note: Don’t name a variable named table you will shadow the inbuilt function table(...)
Javier Cabello
Javier Cabello 2020-6-3
Awesome! thanks for your help. Also thanks for noting the conflict with the function table, I just used it as a name here for my example.

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