Inconsistent handles structure in GUI callback function
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I have a GUI which displays an image (it's a colormap, and each pixel contains signal data.) I want to be able to click a pixel and display a graph of the signal data that was stored in that pixel. That part works fine, the errors pop up when I try to select a second pixel. My intention is to create a subplot on a single figure, 5 rows by 2 columns (the first column is time domain, second is frequency domain.) The GUI would know which row it should be in by a variable "nthline" which is part of the handles structure, and at the end of the callback function, it will increment by 1 and update the handles structure with guidata(hObject, h). At first, it would create brand new figures with the new data which, while worked, is not what I was asked to do, so I continued to try to get it on the same figure, which led to me adding a variable "firstClick" to the handles structure in the GUI. Upon looking at the value of firstClick for the first pixel selection (where firstClick should be true, where it is initialized and saved to the handles structure,) it is indeed saved as true. So, I update the handles structure to assign false to firstclick with
h.firstClick = false; %h is the handles structure
guidata(hObject, h);
On the second pixel selection, h.firstClick is still true, and so it reopens a new figure, but this is not what I want. Why is there this inconsistency in handles structures across different pixels, and how can I keep the firstClick variable from changing back to true?
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Steven Lord
2020-6-3
My guess is that you specified the callback function that executes as an anonymous function that does not accept the handles structure as an input but instead "remembers" it.
m = 5;
b = 3;
y = @(x) m*x+b;
y(2) % 13
m = 999;
y(2) % still 13
Instead, pass something that's not likely to change (the handle to your UI perhaps) but with which you can access the handles struct into the callback.
f = figure;
f.UserData = [5 3];
computeme = @(x, fig) fig.UserData(1)*x + fig.UserData(2)
y = @(x) computeme(x, f);
y(2) % still 13
f.UserData = [42, 26];
y(2) % 42*2+26 = 110
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