Pattern search and string indexing

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Ronald
Ronald 2020-6-4
评论： Ameer Hamza 2020-6-5
I have two cell arrays:
A = {[x(2)& x(4)& x(1)],[x(3),x(5)],[x(2),x(1)]}
B = {2465,2514,147,236,58}
where the integers in A are the indices of B items. I want to replace those indices with actual values as:
C = {[2514,236,2465],[147,58],[2514,2465]}
For loop is a bit slow. Is there an alternative?

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采纳的回答

Ameer Hamza
Ameer Hamza 2020-6-4
Something like this
A = {[2 4 1],[3 5],[2 1]}; % you can put indexes as numbers
B = {2465,2514,147,236,58};
A_new = cellfun(@(x) {[B{x}]}, A)
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Ronald
Ronald 2020-6-4
By the way, can we set a separator in the output here?
Ameer Hamza
Ameer Hamza 2020-6-4
Can you explain what do you mean by separator?

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更多回答（1 个）

madhan ravi
madhan ravi 2020-6-4
A = @(x){[x(2), x(4), x(1)],[x(3),x(5)],[x(2),x(1)]}
B = {2465,2514,147,236,58}
C = A(B)
  2 个评论
Ronald
Ronald 2020-6-4
Thanks mate! However, I found out that it couldn't slice A nicely as I wanted.
Ameer Hamza
Ameer Hamza 2020-6-5
FYI, following code will slice A as you want
C = A([B{:}])

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