how to generate a polynomial

2012 11 24
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0 个投票

i have two matrix one is
s=[2 3
4 5]
other is
text = [3 5 6 7
3 4 5 6]
based on my threshold value i should form a polynomial
say for exam threshold is 2 my polynomial should be
P= s(1,1)*x^0 + text(1,1)*x^1
if threshold is 3 my polynomial should be
P= s(1,1)*x^0 + text(1,1)*x^1 + text(1,2)*x^2 i have to process for every
digit like this .... value from should be taken once but from text van be any
number of times based on threshold...
Thanks in advance ..i am not able to trace it out please help

15 个评论
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Azzi Abdelmalek
Azzi Abdelmalek 2012-11-24
is it always s(1,1)?
Matt Fig
Matt Fig 2012-11-24
Yes, what is the general pattern? Are the other elements of S never used?
Sharen H
Sharen H 2012-11-24
its like s(i,j) and the polynomial is generated for every pixel ie p(i,j)
finally i should have a polynomial for every s pixel
Walter Roberson
Walter Roberson 2012-11-24
Your "text" is a matrix. When is the second row of the matrix used?
Matt Fig
Matt Fig 2012-11-24
编辑：Matt Fig 2012-11-24
Yet still you don't reveal the general pattern....
P(m,n) = _________________________
(for m = 1:size(s,1) and n = 1:size(s,2) ????)
Fill in the blank and clarify the ranges.
Sharen H
Sharen H 2012-11-24
okok i am not knowing how to explain please
i have a secret matrix s= [2 1 ; 3 4]
similarly a text matrix t=[2 3 4 ; 5 6 7,5 6 7] it can be any size
i have to combine this and generate a polynomial p which should have the same size of s
polynomial chooses values based on the threshold if threshold is 3 one value from s and others from text always only one from s matrix
ie p=
[s(1,1)+t(1,1)*x^1+t(1,2)*x^2 s(1,2)+t(1,3)*x^1+t(2,1)*x^2
[s(2,1)+t(2,2)*x^1+t(2,3)*x^2 s(2,2)+t(3,1)*x^1+t(3,2)*x^2 ]
when i substitute for x it becomes a matrix p. the remaining values of text can be left without
processing
am i clear thanks a lot for helping
Sharen H
Sharen H 2012-11-24
Degree of the polynomial should be threshold-1
Azzi Abdelmalek
Azzi Abdelmalek 2012-11-24
It's still not clear for me, what does that mean
s(1,2)+t(1,3)*x^1+t(2,1)*x^2
Sharen H
Sharen H 2012-11-24
编辑：Sharen H 2012-11-24
first digit of the polynomial is from the s matrix and other two digits from text matrix
Azzi Abdelmalek
Azzi Abdelmalek 2012-11-24
for s it's clear, how are using t?
Sharen H
Sharen H 2012-11-24
if threshold is 3 for s(1,1) i take first two values from t, then for s(1,2) the next two values from t matrix it goes like that ..
if threshold is 4 i have to take 3 values from t matrix
Walter Roberson
Walter Roberson 2012-11-24
So if your threshold is N, you take N-1 consecutive entries from t, proceeding along columns, and "wrapping" along to the next row ?
Sharen H
Sharen H 2012-11-24
编辑：Sharen H 2012-11-24
yes
Azzi Abdelmalek
Azzi Abdelmalek 2012-11-24
编辑：Azzi Abdelmalek 2012-11-24
Then why t(2,1) is repeated?

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 采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2012-11-24
编辑：Azzi Abdelmalek 2012-11-24

1 个投票

s=[2 3 ;4 5]
text = [2 3 4; 5 6 7; 4 5 6]
t=text.'
t=t(:)
th=3;
x=11
[n,m]=size(s)
c=1:th-1;
idx1=1;
idx2=th-1;
for k=1:n
for l=1:m
t1=t(idx1:idx2).'
P(k,l)=s(k,l)+sum(t1.*x.^c)
idx1=idx1+th-1
idx2=idx2+th-1
end
end

3 个评论
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Walter Roberson
Walter Roberson 2012-11-24
Minor correction: use .' instead of ' as in theory t could contain complex numbers.
Azzi Abdelmalek
Azzi Abdelmalek 2012-11-24
Ok Walter, It's done
Sharen H
Sharen H 2012-11-25
thanks a lot ....It works perfectly

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更多回答（2 个）

Azzi Abdelmalek
Azzi Abdelmalek 2012-11-24
编辑：Azzi Abdelmalek 2012-11-24

0 个投票

s=[2 3 ;4 5]
text = [3 5 6 7 3 4 5 6]
threshold=4;
x=11
c=1:threshold-1
P=s(1,1)+sum(text(c).*x.^c)

2 个评论
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Sharen H
Sharen H 2012-11-24
the value of text should be incremented for s(1,2)
Azzi Abdelmalek
Azzi Abdelmalek 2012-11-24
If threshold=3 what should be the result?

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Matt Fig
Matt Fig 2012-11-24

0 个投票

Sharen, please fill in the blank and define the ranges:
P(m,n) = _________________________
(for m = 1:size(s,1) and n = 1:size(s,2)) <---- correct??

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